Optimal. Leaf size=933 \[ \frac{(2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^3}{2 \sqrt{c} g (e f-d g)^4}-\frac{\sqrt{c f^2-b g f+a g^2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e^3}{g (e f-d g)^4}-\frac{\sqrt{c} \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^2}{g (e f-d g)^3}-\frac{(2 c d-b e) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^2}{2 \sqrt{c} (e f-d g)^4}+\frac{\sqrt{c d^2-b e d+a e^2} \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b e d+a e^2} \sqrt{c x^2+b x+a}}\right ) e^2}{(e f-d g)^4}+\frac{(2 c f-b g) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e^2}{2 g (e f-d g)^3 \sqrt{c f^2-b g f+a g^2}}+\frac{\sqrt{c x^2+b x+a} e^2}{(e f-d g)^3 (f+g x)}+\frac{\left (b^2-4 a c\right ) g \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e}{8 (e f-d g)^2 \left (c f^2-b g f+a g^2\right )^{3/2}}-\frac{g (b f-2 a g+(2 c f-b g) x) \sqrt{c x^2+b x+a} e}{4 (e f-d g)^2 \left (c f^2-b g f+a g^2\right ) (f+g x)^2}+\frac{g^2 \left (c x^2+b x+a\right )^{3/2}}{3 (e f-d g) \left (c f^2-b g f+a g^2\right ) (f+g x)^3}+\frac{\left (b^2-4 a c\right ) g (2 c f-b g) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right )}{16 (e f-d g) \left (c f^2-b g f+a g^2\right )^{5/2}}-\frac{g (2 c f-b g) (b f-2 a g+(2 c f-b g) x) \sqrt{c x^2+b x+a}}{8 (e f-d g) \left (c f^2-b g f+a g^2\right )^2 (f+g x)^2} \]
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Rubi [A] time = 1.22482, antiderivative size = 933, normalized size of antiderivative = 1., number of steps used = 27, number of rules used = 9, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.31, Rules used = {960, 734, 843, 621, 206, 724, 730, 720, 732} \[ \frac{(2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^3}{2 \sqrt{c} g (e f-d g)^4}-\frac{\sqrt{c f^2-b g f+a g^2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e^3}{g (e f-d g)^4}-\frac{\sqrt{c} \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^2}{g (e f-d g)^3}-\frac{(2 c d-b e) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^2}{2 \sqrt{c} (e f-d g)^4}+\frac{\sqrt{c d^2-b e d+a e^2} \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b e d+a e^2} \sqrt{c x^2+b x+a}}\right ) e^2}{(e f-d g)^4}+\frac{(2 c f-b g) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e^2}{2 g (e f-d g)^3 \sqrt{c f^2-b g f+a g^2}}+\frac{\sqrt{c x^2+b x+a} e^2}{(e f-d g)^3 (f+g x)}+\frac{\left (b^2-4 a c\right ) g \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e}{8 (e f-d g)^2 \left (c f^2-b g f+a g^2\right )^{3/2}}-\frac{g (b f-2 a g+(2 c f-b g) x) \sqrt{c x^2+b x+a} e}{4 (e f-d g)^2 \left (c f^2-b g f+a g^2\right ) (f+g x)^2}+\frac{g^2 \left (c x^2+b x+a\right )^{3/2}}{3 (e f-d g) \left (c f^2-b g f+a g^2\right ) (f+g x)^3}+\frac{\left (b^2-4 a c\right ) g (2 c f-b g) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right )}{16 (e f-d g) \left (c f^2-b g f+a g^2\right )^{5/2}}-\frac{g (2 c f-b g) (b f-2 a g+(2 c f-b g) x) \sqrt{c x^2+b x+a}}{8 (e f-d g) \left (c f^2-b g f+a g^2\right )^2 (f+g x)^2} \]
Antiderivative was successfully verified.
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Rule 960
Rule 734
Rule 843
Rule 621
Rule 206
Rule 724
Rule 730
Rule 720
Rule 732
Rubi steps
\begin{align*} \int \frac{\sqrt{a+b x+c x^2}}{(d+e x) (f+g x)^4} \, dx &=\int \left (\frac{e^4 \sqrt{a+b x+c x^2}}{(e f-d g)^4 (d+e x)}-\frac{g \sqrt{a+b x+c x^2}}{(e f-d g) (f+g x)^4}-\frac{e g \sqrt{a+b x+c x^2}}{(e f-d g)^2 (f+g x)^3}-\frac{e^2 g \sqrt{a+b x+c x^2}}{(e f-d g)^3 (f+g x)^2}-\frac{e^3 g \sqrt{a+b x+c x^2}}{(e f-d g)^4 (f+g x)}\right ) \, dx\\ &=\frac{e^4 \int \frac{\sqrt{a+b x+c x^2}}{d+e x} \, dx}{(e f-d g)^4}-\frac{\left (e^3 g\right ) \int \frac{\sqrt{a+b x+c x^2}}{f+g x} \, dx}{(e f-d g)^4}-\frac{\left (e^2 g\right ) \int \frac{\sqrt{a+b x+c x^2}}{(f+g x)^2} \, dx}{(e f-d g)^3}-\frac{(e g) \int \frac{\sqrt{a+b x+c x^2}}{(f+g x)^3} \, dx}{(e f-d g)^2}-\frac{g \int \frac{\sqrt{a+b x+c x^2}}{(f+g x)^4} \, dx}{e f-d g}\\ &=\frac{e^2 \sqrt{a+b x+c x^2}}{(e f-d g)^3 (f+g x)}-\frac{e g (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{4 (e f-d g)^2 \left (c f^2-b f g+a g^2\right ) (f+g x)^2}+\frac{g^2 \left (a+b x+c x^2\right )^{3/2}}{3 (e f-d g) \left (c f^2-b f g+a g^2\right ) (f+g x)^3}-\frac{e^3 \int \frac{b d-2 a e+(2 c d-b e) x}{(d+e x) \sqrt{a+b x+c x^2}} \, dx}{2 (e f-d g)^4}+\frac{e^3 \int \frac{b f-2 a g+(2 c f-b g) x}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{2 (e f-d g)^4}-\frac{e^2 \int \frac{b+2 c x}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{2 (e f-d g)^3}+\frac{\left (\left (b^2-4 a c\right ) e g\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{8 (e f-d g)^2 \left (c f^2-b f g+a g^2\right )}-\frac{(g (2 c f-b g)) \int \frac{\sqrt{a+b x+c x^2}}{(f+g x)^3} \, dx}{2 (e f-d g) \left (c f^2-b f g+a g^2\right )}\\ &=\frac{e^2 \sqrt{a+b x+c x^2}}{(e f-d g)^3 (f+g x)}-\frac{g (2 c f-b g) (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{8 (e f-d g) \left (c f^2-b f g+a g^2\right )^2 (f+g x)^2}-\frac{e g (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{4 (e f-d g)^2 \left (c f^2-b f g+a g^2\right ) (f+g x)^2}+\frac{g^2 \left (a+b x+c x^2\right )^{3/2}}{3 (e f-d g) \left (c f^2-b f g+a g^2\right ) (f+g x)^3}-\frac{\left (e^2 (2 c d-b e)\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{2 (e f-d g)^4}+\frac{\left (e^2 \left (c d^2-b d e+a e^2\right )\right ) \int \frac{1}{(d+e x) \sqrt{a+b x+c x^2}} \, dx}{(e f-d g)^4}+\frac{\left (e^3 (2 c f-b g)\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{2 g (e f-d g)^4}-\frac{\left (c e^2\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{g (e f-d g)^3}+\frac{\left (e^2 (2 c f-b g)\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{2 g (e f-d g)^3}+\frac{\left (\left (b^2-4 a c\right ) g (2 c f-b g)\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{16 (e f-d g) \left (c f^2-b f g+a g^2\right )^2}-\frac{\left (\left (b^2-4 a c\right ) e g\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{4 (e f-d g)^2 \left (c f^2-b f g+a g^2\right )}-\frac{\left (e^3 \left (c f^2-b f g+a g^2\right )\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{g (e f-d g)^4}\\ &=\frac{e^2 \sqrt{a+b x+c x^2}}{(e f-d g)^3 (f+g x)}-\frac{g (2 c f-b g) (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{8 (e f-d g) \left (c f^2-b f g+a g^2\right )^2 (f+g x)^2}-\frac{e g (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{4 (e f-d g)^2 \left (c f^2-b f g+a g^2\right ) (f+g x)^2}+\frac{g^2 \left (a+b x+c x^2\right )^{3/2}}{3 (e f-d g) \left (c f^2-b f g+a g^2\right ) (f+g x)^3}+\frac{\left (b^2-4 a c\right ) e g \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{8 (e f-d g)^2 \left (c f^2-b f g+a g^2\right )^{3/2}}-\frac{\left (e^2 (2 c d-b e)\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{(e f-d g)^4}-\frac{\left (2 e^2 \left (c d^2-b d e+a e^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c d^2-4 b d e+4 a e^2-x^2} \, dx,x,\frac{-b d+2 a e-(2 c d-b e) x}{\sqrt{a+b x+c x^2}}\right )}{(e f-d g)^4}+\frac{\left (e^3 (2 c f-b g)\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{g (e f-d g)^4}-\frac{\left (2 c e^2\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{g (e f-d g)^3}-\frac{\left (e^2 (2 c f-b g)\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{g (e f-d g)^3}-\frac{\left (\left (b^2-4 a c\right ) g (2 c f-b g)\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{8 (e f-d g) \left (c f^2-b f g+a g^2\right )^2}+\frac{\left (2 e^3 \left (c f^2-b f g+a g^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{g (e f-d g)^4}\\ &=\frac{e^2 \sqrt{a+b x+c x^2}}{(e f-d g)^3 (f+g x)}-\frac{g (2 c f-b g) (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{8 (e f-d g) \left (c f^2-b f g+a g^2\right )^2 (f+g x)^2}-\frac{e g (b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{4 (e f-d g)^2 \left (c f^2-b f g+a g^2\right ) (f+g x)^2}+\frac{g^2 \left (a+b x+c x^2\right )^{3/2}}{3 (e f-d g) \left (c f^2-b f g+a g^2\right ) (f+g x)^3}-\frac{e^2 (2 c d-b e) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{2 \sqrt{c} (e f-d g)^4}+\frac{e^3 (2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{2 \sqrt{c} g (e f-d g)^4}-\frac{\sqrt{c} e^2 \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{g (e f-d g)^3}+\frac{e^2 \sqrt{c d^2-b d e+a e^2} \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b d e+a e^2} \sqrt{a+b x+c x^2}}\right )}{(e f-d g)^4}+\frac{\left (b^2-4 a c\right ) g (2 c f-b g) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{16 (e f-d g) \left (c f^2-b f g+a g^2\right )^{5/2}}+\frac{\left (b^2-4 a c\right ) e g \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{8 (e f-d g)^2 \left (c f^2-b f g+a g^2\right )^{3/2}}+\frac{e^2 (2 c f-b g) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{2 g (e f-d g)^3 \sqrt{c f^2-b f g+a g^2}}-\frac{e^3 \sqrt{c f^2-b f g+a g^2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{g (e f-d g)^4}\\ \end{align*}
Mathematica [A] time = 4.87107, size = 858, normalized size = 0.92 \[ \frac{\frac{24 \left ((2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )-2 \sqrt{c} \sqrt{c f^2+g (a g-b f)} \tanh ^{-1}\left (\frac{-2 a g+2 c f x+b (f-g x)}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right )\right ) e^3}{\sqrt{c} g}+24 \left (\frac{(b e-2 c d) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )}{\sqrt{c}}+2 \sqrt{c d^2+e (a e-b d)} \tanh ^{-1}\left (\frac{-2 a e+2 c d x+b (d-e x)}{2 \sqrt{c d^2+e (a e-b d)} \sqrt{a+x (b+c x)}}\right )\right ) e^2-\frac{24 (e f-d g) \left (2 \sqrt{c} \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )-\frac{(2 c f-b g) \tanh ^{-1}\left (\frac{-2 a g+2 c f x+b (f-g x)}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right )}{\sqrt{c f^2+g (a g-b f)}}\right ) e^2}{g}+\frac{48 (e f-d g) \sqrt{a+x (b+c x)} e^2}{f+g x}+\frac{6 \left (b^2-4 a c\right ) g (e f-d g)^2 \tanh ^{-1}\left (\frac{-2 a g+2 c f x+b (f-g x)}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right ) e}{\left (c f^2+g (a g-b f)\right )^{3/2}}+\frac{12 g (e f-d g)^2 (-b f-2 c x f+2 a g+b g x) \sqrt{a+x (b+c x)} e}{\left (c f^2+g (a g-b f)\right ) (f+g x)^2}-\frac{16 g^2 (d g-e f)^3 (a+x (b+c x))^{3/2}}{\left (c f^2+g (a g-b f)\right ) (f+g x)^3}-\frac{3 g (2 c f-b g) (e f-d g)^3 \left (\frac{2 \sqrt{a+x (b+c x)} (-2 a g+2 c f x+b (f-g x))}{\left (c f^2+g (a g-b f)\right ) (f+g x)^2}+\frac{\left (4 a c-b^2\right ) \tanh ^{-1}\left (\frac{-2 a g+2 c f x+b (f-g x)}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right )}{\left (c f^2+g (a g-b f)\right )^{3/2}}\right )}{c f^2+g (a g-b f)}}{48 (e f-d g)^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.329, size = 11995, normalized size = 12.9 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{c x^{2} + b x + a}}{{\left (e x + d\right )}{\left (g x + f\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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